7(z+3)=6(z-4)+z

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Solution for 7(z+3)=6(z-4)+z equation:


Simplifying
7(z + 3) = 6(z + -4) + z

Reorder the terms:
7(3 + z) = 6(z + -4) + z
(3 * 7 + z * 7) = 6(z + -4) + z
(21 + 7z) = 6(z + -4) + z

Reorder the terms:
21 + 7z = 6(-4 + z) + z
21 + 7z = (-4 * 6 + z * 6) + z
21 + 7z = (-24 + 6z) + z

Combine like terms: 6z + z = 7z
21 + 7z = -24 + 7z

Add '-7z' to each side of the equation.
21 + 7z + -7z = -24 + 7z + -7z

Combine like terms: 7z + -7z = 0
21 + 0 = -24 + 7z + -7z
21 = -24 + 7z + -7z

Combine like terms: 7z + -7z = 0
21 = -24 + 0
21 = -24

Solving
21 = -24

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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