7(y-8)=3(y+4)

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Solution for 7(y-8)=3(y+4) equation: 



7(y-8)=3(y+4)

We move all terms to the left:

7(y-8)-(3(y+4))=0

We multiply parentheses

7y-(3(y+4))-56=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

7y-3y-12-56=0

We add all the numbers together, and all the variables

4y-68=0

We move all terms containing y to the left, all other terms to the right

4y=68

y=68/4

y=17

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