7(y-6)+4y=35

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Solution for 7(y-6)+4y=35 equation: 



7(y-6)+4y=35

We move all terms to the left:

7(y-6)+4y-(35)=0

We add all the numbers together, and all the variables

4y+7(y-6)-35=0

We multiply parentheses

4y+7y-42-35=0

We add all the numbers together, and all the variables

11y-77=0

We move all terms containing y to the left, all other terms to the right

11y=77

y=77/11

y=7

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