7(y-5)+3y=10(y-1)

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Solution for 7(y-5)+3y=10(y-1) equation: 



7(y-5)+3y=10(y-1)

We move all terms to the left:

7(y-5)+3y-(10(y-1))=0

We add all the numbers together, and all the variables

3y+7(y-5)-(10(y-1))=0

We multiply parentheses

3y+7y-(10(y-1))-35=0



We calculate terms in parentheses: -(10(y-1)), so:

10(y-1)

We multiply parentheses

10y-10

Back to the equation:

-(10y-10)



We add all the numbers together, and all the variables

10y-(10y-10)-35=0

We get rid of parentheses

10y-10y+10-35=0

We add all the numbers together, and all the variables

-25!=0

There is no solution for this equation

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