7(y-5)+3=10(y+1)

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Solution for 7(y-5)+3=10(y+1) equation: 



7(y-5)+3=10(y+1)

We move all terms to the left:

7(y-5)+3-(10(y+1))=0

We multiply parentheses

7y-(10(y+1))-35+3=0



We calculate terms in parentheses: -(10(y+1)), so:

10(y+1)

We multiply parentheses

10y+10

Back to the equation:

-(10y+10)



We add all the numbers together, and all the variables

7y-(10y+10)-32=0

We get rid of parentheses

7y-10y-10-32=0

We add all the numbers together, and all the variables

-3y-42=0

We move all terms containing y to the left, all other terms to the right

-3y=42

y=42/-3

y=-14

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