7(y-4)=2(3y+7)-42

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Solution for 7(y-4)=2(3y+7)-42 equation:


Simplifying
7(y + -4) = 2(3y + 7) + -42

Reorder the terms:
7(-4 + y) = 2(3y + 7) + -42
(-4 * 7 + y * 7) = 2(3y + 7) + -42
(-28 + 7y) = 2(3y + 7) + -42

Reorder the terms:
-28 + 7y = 2(7 + 3y) + -42
-28 + 7y = (7 * 2 + 3y * 2) + -42
-28 + 7y = (14 + 6y) + -42

Reorder the terms:
-28 + 7y = 14 + -42 + 6y

Combine like terms: 14 + -42 = -28
-28 + 7y = -28 + 6y

Add '28' to each side of the equation.
-28 + 28 + 7y = -28 + 28 + 6y

Combine like terms: -28 + 28 = 0
0 + 7y = -28 + 28 + 6y
7y = -28 + 28 + 6y

Combine like terms: -28 + 28 = 0
7y = 0 + 6y
7y = 6y

Solving
7y = 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
7y + -6y = 6y + -6y

Combine like terms: 7y + -6y = 1y
1y = 6y + -6y

Combine like terms: 6y + -6y = 0
1y = 0

Divide each side by '1'.
y = 0

Simplifying
y = 0

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