7(y-4)=-8y-13

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Solution for 7(y-4)=-8y-13 equation: 



7(y-4)=-8y-13

We move all terms to the left:

7(y-4)-(-8y-13)=0

We multiply parentheses

7y-(-8y-13)-28=0

We get rid of parentheses

7y+8y+13-28=0

We add all the numbers together, and all the variables

15y-15=0

We move all terms containing y to the left, all other terms to the right

15y=15

y=15/15

y=1

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