7(y-4)+6(y+1)=17

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Solution for 7(y-4)+6(y+1)=17 equation:


Simplifying
7(y + -4) + 6(y + 1) = 17

Reorder the terms:
7(-4 + y) + 6(y + 1) = 17
(-4 * 7 + y * 7) + 6(y + 1) = 17
(-28 + 7y) + 6(y + 1) = 17

Reorder the terms:
-28 + 7y + 6(1 + y) = 17
-28 + 7y + (1 * 6 + y * 6) = 17
-28 + 7y + (6 + 6y) = 17

Reorder the terms:
-28 + 6 + 7y + 6y = 17

Combine like terms: -28 + 6 = -22
-22 + 7y + 6y = 17

Combine like terms: 7y + 6y = 13y
-22 + 13y = 17

Solving
-22 + 13y = 17

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 13y = 17 + 22

Combine like terms: -22 + 22 = 0
0 + 13y = 17 + 22
13y = 17 + 22

Combine like terms: 17 + 22 = 39
13y = 39

Divide each side by '13'.
y = 3

Simplifying
y = 3

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