7(y-4)+2(y+3)=23

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Solution for 7(y-4)+2(y+3)=23 equation: 



7(y-4)+2(y+3)=23

We move all terms to the left:

7(y-4)+2(y+3)-(23)=0

We multiply parentheses

7y+2y-28+6-23=0

We add all the numbers together, and all the variables

9y-45=0

We move all terms containing y to the left, all other terms to the right

9y=45

y=45/9

y=5

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