7(y-4)+2(y+1)=28

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Solution for 7(y-4)+2(y+1)=28 equation:


Simplifying
7(y + -4) + 2(y + 1) = 28

Reorder the terms:
7(-4 + y) + 2(y + 1) = 28
(-4 * 7 + y * 7) + 2(y + 1) = 28
(-28 + 7y) + 2(y + 1) = 28

Reorder the terms:
-28 + 7y + 2(1 + y) = 28
-28 + 7y + (1 * 2 + y * 2) = 28
-28 + 7y + (2 + 2y) = 28

Reorder the terms:
-28 + 2 + 7y + 2y = 28

Combine like terms: -28 + 2 = -26
-26 + 7y + 2y = 28

Combine like terms: 7y + 2y = 9y
-26 + 9y = 28

Solving
-26 + 9y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '26' to each side of the equation.
-26 + 26 + 9y = 28 + 26

Combine like terms: -26 + 26 = 0
0 + 9y = 28 + 26
9y = 28 + 26

Combine like terms: 28 + 26 = 54
9y = 54

Divide each side by '9'.
y = 6

Simplifying
y = 6

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