7(y-3)=3y-49

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Solution for 7(y-3)=3y-49 equation: 



7(y-3)=3y-49

We move all terms to the left:

7(y-3)-(3y-49)=0

We multiply parentheses

7y-(3y-49)-21=0

We get rid of parentheses

7y-3y+49-21=0

We add all the numbers together, and all the variables

4y+28=0

We move all terms containing y to the left, all other terms to the right

4y=-28

y=-28/4

y=-7

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