7(y-3)=2(y-9)+9

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Solution for 7(y-3)=2(y-9)+9 equation: 



7(y-3)=2(y-9)+9

We move all terms to the left:

7(y-3)-(2(y-9)+9)=0

We multiply parentheses

7y-(2(y-9)+9)-21=0



We calculate terms in parentheses: -(2(y-9)+9), so:

2(y-9)+9

We multiply parentheses

2y-18+9

We add all the numbers together, and all the variables

2y-9

Back to the equation:

-(2y-9)



We get rid of parentheses

7y-2y+9-21=0

We add all the numbers together, and all the variables

5y-12=0

We move all terms containing y to the left, all other terms to the right

5y=12

y=12/5

y=2+2/5

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