7(y-3)=-2(-2y+4)+10

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Solution for 7(y-3)=-2(-2y+4)+10 equation: 



7(y-3)=-2(-2y+4)+10

We move all terms to the left:

7(y-3)-(-2(-2y+4)+10)=0

We multiply parentheses

7y-(-2(-2y+4)+10)-21=0



We calculate terms in parentheses: -(-2(-2y+4)+10), so:

-2(-2y+4)+10

We multiply parentheses

4y-8+10

We add all the numbers together, and all the variables

4y+2

Back to the equation:

-(4y+2)



We get rid of parentheses

7y-4y-2-21=0

We add all the numbers together, and all the variables

3y-23=0

We move all terms containing y to the left, all other terms to the right

3y=23

y=23/3

y=7+2/3

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