7(y-3)-3=-3(-7y+4)-6y

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Solution for 7(y-3)-3=-3(-7y+4)-6y equation: 



7(y-3)-3=-3(-7y+4)-6y

We move all terms to the left:

7(y-3)-3-(-3(-7y+4)-6y)=0

We multiply parentheses

7y-(-3(-7y+4)-6y)-21-3=0



We calculate terms in parentheses: -(-3(-7y+4)-6y), so:

-3(-7y+4)-6y

We add all the numbers together, and all the variables

-6y-3(-7y+4)

We multiply parentheses

-6y+21y-12

We add all the numbers together, and all the variables

15y-12

Back to the equation:

-(15y-12)



We add all the numbers together, and all the variables

7y-(15y-12)-24=0

We get rid of parentheses

7y-15y+12-24=0

We add all the numbers together, and all the variables

-8y-12=0

We move all terms containing y to the left, all other terms to the right

-8y=12

y=12/-8

y=-1+1/2

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