7(y-2)=3(y-1)

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Solution for 7(y-2)=3(y-1) equation: 



7(y-2)=3(y-1)

We move all terms to the left:

7(y-2)-(3(y-1))=0

We multiply parentheses

7y-(3(y-1))-14=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

7y-3y+3-14=0

We add all the numbers together, and all the variables

4y-11=0

We move all terms containing y to the left, all other terms to the right

4y=11

y=11/4

y=2+3/4

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