7(y-1)=5y+1-2(-7y-5)

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Solution for 7(y-1)=5y+1-2(-7y-5) equation: 



7(y-1)=5y+1-2(-7y-5)

We move all terms to the left:

7(y-1)-(5y+1-2(-7y-5))=0

We multiply parentheses

7y-(5y+1-2(-7y-5))-7=0



We calculate terms in parentheses: -(5y+1-2(-7y-5)), so:

5y+1-2(-7y-5)

determiningTheFunctionDomain
5y-2(-7y-5)+1

We multiply parentheses

5y+14y+10+1

We add all the numbers together, and all the variables

19y+11

Back to the equation:

-(19y+11)



We get rid of parentheses

7y-19y-11-7=0

We add all the numbers together, and all the variables

-12y-18=0

We move all terms containing y to the left, all other terms to the right

-12y=18

y=18/-12

y=-1+1/2

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