7(y+6)+y=2(y+2)+2=

Solution for 7(y+6)+y=2(y+2)+2= equation:

7(y+6)+y=2(y+2)+2=

We move all terms to the left:

7(y+6)+y-(2(y+2)+2)=0

We add all the numbers together, and all the variables

y+7(y+6)-(2(y+2)+2)=0

We multiply parentheses

y+7y-(2(y+2)+2)+42=0


We calculate terms in parentheses: -(2(y+2)+2), so:

2(y+2)+2

We multiply parentheses

2y+4+2

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)


We add all the numbers together, and all the variables

8y-(2y+6)+42=0

We get rid of parentheses

8y-2y-6+42=0

We add all the numbers together, and all the variables

6y+36=0

We move all terms containing y to the left, all other terms to the right

6y=-36

y=-36/6

y=-6