7(y+5)+y=2(y+3)-8

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Solution for 7(y+5)+y=2(y+3)-8 equation:


Simplifying
7(y + 5) + y = 2(y + 3) + -8

Reorder the terms:
7(5 + y) + y = 2(y + 3) + -8
(5 * 7 + y * 7) + y = 2(y + 3) + -8
(35 + 7y) + y = 2(y + 3) + -8

Combine like terms: 7y + y = 8y
35 + 8y = 2(y + 3) + -8

Reorder the terms:
35 + 8y = 2(3 + y) + -8
35 + 8y = (3 * 2 + y * 2) + -8
35 + 8y = (6 + 2y) + -8

Reorder the terms:
35 + 8y = 6 + -8 + 2y

Combine like terms: 6 + -8 = -2
35 + 8y = -2 + 2y

Solving
35 + 8y = -2 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
35 + 8y + -2y = -2 + 2y + -2y

Combine like terms: 8y + -2y = 6y
35 + 6y = -2 + 2y + -2y

Combine like terms: 2y + -2y = 0
35 + 6y = -2 + 0
35 + 6y = -2

Add '-35' to each side of the equation.
35 + -35 + 6y = -2 + -35

Combine like terms: 35 + -35 = 0
0 + 6y = -2 + -35
6y = -2 + -35

Combine like terms: -2 + -35 = -37
6y = -37

Divide each side by '6'.
y = -6.166666667

Simplifying
y = -6.166666667

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