7(y+4)-3(y-5)=6y+35

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Solution for 7(y+4)-3(y-5)=6y+35 equation: 



7(y+4)-3(y-5)=6y+35

We move all terms to the left:

7(y+4)-3(y-5)-(6y+35)=0

We multiply parentheses

7y-3y-(6y+35)+28+15=0

We get rid of parentheses

7y-3y-6y-35+28+15=0

We add all the numbers together, and all the variables

-2y+8=0

We move all terms containing y to the left, all other terms to the right

-2y=-8

y=-8/-2

y=+4

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