7(y+3)=2y+26

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Solution for 7(y+3)=2y+26 equation: 



7(y+3)=2y+26

We move all terms to the left:

7(y+3)-(2y+26)=0

We multiply parentheses

7y-(2y+26)+21=0

We get rid of parentheses

7y-2y-26+21=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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