7(y+1)=3y+1

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Solution for 7(y+1)=3y+1 equation: 



7(y+1)=3y+1

We move all terms to the left:

7(y+1)-(3y+1)=0

We multiply parentheses

7y-(3y+1)+7=0

We get rid of parentheses

7y-3y-1+7=0

We add all the numbers together, and all the variables

4y+6=0

We move all terms containing y to the left, all other terms to the right

4y=-6

y=-6/4

y=-1+1/2

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