7(y+1)+2=3(2y-1)

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Solution for 7(y+1)+2=3(2y-1) equation: 



7(y+1)+2=3(2y-1)

We move all terms to the left:

7(y+1)+2-(3(2y-1))=0

We multiply parentheses

7y-(3(2y-1))+7+2=0



We calculate terms in parentheses: -(3(2y-1)), so:

3(2y-1)

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)



We add all the numbers together, and all the variables

7y-(6y-3)+9=0

We get rid of parentheses

7y-6y+3+9=0

We add all the numbers together, and all the variables

y+12=0

We move all terms containing y to the left, all other terms to the right

y=-12

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