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7(x-9)+3(2x-5)=12(x-5)-7
We move all terms to the left:
7(x-9)+3(2x-5)-(12(x-5)-7)=0
We multiply parentheses
7x+6x-(12(x-5)-7)-63-15=0
We calculate terms in parentheses: -(12(x-5)-7), so:We add all the numbers together, and all the variables
12(x-5)-7
We multiply parentheses
12x-60-7
We add all the numbers together, and all the variables
12x-67
Back to the equation:
-(12x-67)
13x-(12x-67)-78=0
We get rid of parentheses
13x-12x+67-78=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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