7(x-8)+18=2(x-4)

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Solution for 7(x-8)+18=2(x-4) equation: 



7(x-8)+18=2(x-4)

We move all terms to the left:

7(x-8)+18-(2(x-4))=0

We multiply parentheses

7x-(2(x-4))-56+18=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

7x-(2x-8)-38=0

We get rid of parentheses

7x-2x+8-38=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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