7(x-7)-3x=5-2(x+3)+4x

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Solution for 7(x-7)-3x=5-2(x+3)+4x equation: 



7(x-7)-3x=5-2(x+3)+4x

We move all terms to the left:

7(x-7)-3x-(5-2(x+3)+4x)=0

We add all the numbers together, and all the variables

-3x+7(x-7)-(5-2(x+3)+4x)=0

We multiply parentheses

-3x+7x-(5-2(x+3)+4x)-49=0



We calculate terms in parentheses: -(5-2(x+3)+4x), so:

5-2(x+3)+4x

determiningTheFunctionDomain
-2(x+3)+4x+5

We add all the numbers together, and all the variables

4x-2(x+3)+5

We multiply parentheses

4x-2x-6+5

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

4x-(2x-1)-49=0

We get rid of parentheses

4x-2x+1-49=0

We add all the numbers together, and all the variables

2x-48=0

We move all terms containing x to the left, all other terms to the right

2x=48

x=48/2

x=24

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