7(x-6)=3(x-2)+7x

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Solution for 7(x-6)=3(x-2)+7x equation: 



7(x-6)=3(x-2)+7x

We move all terms to the left:

7(x-6)-(3(x-2)+7x)=0

We multiply parentheses

7x-(3(x-2)+7x)-42=0



We calculate terms in parentheses: -(3(x-2)+7x), so:

3(x-2)+7x

We add all the numbers together, and all the variables

7x+3(x-2)

We multiply parentheses

7x+3x-6

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We get rid of parentheses

7x-10x+6-42=0

We add all the numbers together, and all the variables

-3x-36=0

We move all terms containing x to the left, all other terms to the right

-3x=36

x=36/-3

x=-12

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