7(x-6)(x-8)=0

Solution for 7(x-6)(x-8)=0 equation:

7(x-6)(x-8)=0

We multiply parentheses ..

7(+x^2-8x-6x+48)=0

We multiply parentheses

7x^2-56x-42x+336=0

We add all the numbers together, and all the variables

7x^2-98x+336=0

a = 7; b = -98; c = +336;
Δ = b2-4ac
Δ = -982-4·7·336
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14}{2*7}=\frac{84}{14}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14}{2*7}=\frac{112}{14}
=8
$