7(x-5)=3(x-6)+17

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Solution for 7(x-5)=3(x-6)+17 equation: 



7(x-5)=3(x-6)+17

We move all terms to the left:

7(x-5)-(3(x-6)+17)=0

We multiply parentheses

7x-(3(x-6)+17)-35=0



We calculate terms in parentheses: -(3(x-6)+17), so:

3(x-6)+17

We multiply parentheses

3x-18+17

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We get rid of parentheses

7x-3x+1-35=0

We add all the numbers together, and all the variables

4x-34=0

We move all terms containing x to the left, all other terms to the right

4x=34

x=34/4

x=8+1/2

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