7(x-5)+3x=10(x+1)+11

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Solution for 7(x-5)+3x=10(x+1)+11 equation: 



7(x-5)+3x=10(x+1)+11

We move all terms to the left:

7(x-5)+3x-(10(x+1)+11)=0

We add all the numbers together, and all the variables

3x+7(x-5)-(10(x+1)+11)=0

We multiply parentheses

3x+7x-(10(x+1)+11)-35=0



We calculate terms in parentheses: -(10(x+1)+11), so:

10(x+1)+11

We multiply parentheses

10x+10+11

We add all the numbers together, and all the variables

10x+21

Back to the equation:

-(10x+21)



We add all the numbers together, and all the variables

10x-(10x+21)-35=0

We get rid of parentheses

10x-10x-21-35=0

We add all the numbers together, and all the variables

-56!=0

There is no solution for this equation

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