7(x-4)=9(x+1)-(5-2x)=2(x-4)

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Solution for 7(x-4)=9(x+1)-(5-2x)=2(x-4) equation: 



7(x-4)=9(x+1)-(5-2x)=2(x-4)

We move all terms to the left:

7(x-4)-(9(x+1)-(5-2x))=0

We add all the numbers together, and all the variables

7(x-4)-(9(x+1)-(-2x+5))=0

We multiply parentheses

7x-(9(x+1)-(-2x+5))-28=0



We calculate terms in parentheses: -(9(x+1)-(-2x+5)), so:

9(x+1)-(-2x+5)

We multiply parentheses

9x-(-2x+5)+9

We get rid of parentheses

9x+2x-5+9

We add all the numbers together, and all the variables

11x+4

Back to the equation:

-(11x+4)



We get rid of parentheses

7x-11x-4-28=0

We add all the numbers together, and all the variables

-4x-32=0

We move all terms containing x to the left, all other terms to the right

-4x=32

x=32/-4

x=-8

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