7(x-4)=5x+40

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Solution for 7(x-4)=5x+40 equation: 



7(x-4)=5x+40

We move all terms to the left:

7(x-4)-(5x+40)=0

We multiply parentheses

7x-(5x+40)-28=0

We get rid of parentheses

7x-5x-40-28=0

We add all the numbers together, and all the variables

2x-68=0

We move all terms containing x to the left, all other terms to the right

2x=68

x=68/2

x=34

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