7(x-4)-3x=4(2x+1)

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Solution for 7(x-4)-3x=4(2x+1) equation: 



7(x-4)-3x=4(2x+1)

We move all terms to the left:

7(x-4)-3x-(4(2x+1))=0

We add all the numbers together, and all the variables

-3x+7(x-4)-(4(2x+1))=0

We multiply parentheses

-3x+7x-(4(2x+1))-28=0



We calculate terms in parentheses: -(4(2x+1)), so:

4(2x+1)

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We add all the numbers together, and all the variables

4x-(8x+4)-28=0

We get rid of parentheses

4x-8x-4-28=0

We add all the numbers together, and all the variables

-4x-32=0

We move all terms containing x to the left, all other terms to the right

-4x=32

x=32/-4

x=-8

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