7(x-4)-2(2x+3)=3(x-4)-5(-x)

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Solution for 7(x-4)-2(2x+3)=3(x-4)-5(-x) equation: 



7(x-4)-2(2x+3)=3(x-4)-5(-x)

We move all terms to the left:

7(x-4)-2(2x+3)-(3(x-4)-5(-x))=0

We add all the numbers together, and all the variables

7(x-4)-2(2x+3)-(3(x-4)-5(-1x))=0

We multiply parentheses

7x-4x-(3(x-4)-5(-1x))-28-6=0



We calculate terms in parentheses: -(3(x-4)-5(-1x)), so:

3(x-4)-5(-1x)

We multiply parentheses

3x+5x-12

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

3x-(8x-12)-34=0

We get rid of parentheses

3x-8x+12-34=0

We add all the numbers together, and all the variables

-5x-22=0

We move all terms containing x to the left, all other terms to the right

-5x=22

x=22/-5

x=-4+2/5

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