7(x-4)-10=3x+20+4x-2

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Solution for 7(x-4)-10=3x+20+4x-2 equation: 



7(x-4)-10=3x+20+4x-2

We move all terms to the left:

7(x-4)-10-(3x+20+4x-2)=0

We add all the numbers together, and all the variables

7(x-4)-(7x+18)-10=0

We multiply parentheses

7x-(7x+18)-28-10=0

We get rid of parentheses

7x-7x-18-28-10=0

We add all the numbers together, and all the variables

-56!=0

There is no solution for this equation

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