7(x-4)+x=8(x-5)+12

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Solution for 7(x-4)+x=8(x-5)+12 equation:


Simplifying
7(x + -4) + x = 8(x + -5) + 12

Reorder the terms:
7(-4 + x) + x = 8(x + -5) + 12
(-4 * 7 + x * 7) + x = 8(x + -5) + 12
(-28 + 7x) + x = 8(x + -5) + 12

Combine like terms: 7x + x = 8x
-28 + 8x = 8(x + -5) + 12

Reorder the terms:
-28 + 8x = 8(-5 + x) + 12
-28 + 8x = (-5 * 8 + x * 8) + 12
-28 + 8x = (-40 + 8x) + 12

Reorder the terms:
-28 + 8x = -40 + 12 + 8x

Combine like terms: -40 + 12 = -28
-28 + 8x = -28 + 8x

Add '28' to each side of the equation.
-28 + 28 + 8x = -28 + 28 + 8x

Combine like terms: -28 + 28 = 0
0 + 8x = -28 + 28 + 8x
8x = -28 + 28 + 8x

Combine like terms: -28 + 28 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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