7(x-4)+8=3x+4(-4+x)

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Solution for 7(x-4)+8=3x+4(-4+x) equation: 



7(x-4)+8=3x+4(-4+x)

We move all terms to the left:

7(x-4)+8-(3x+4(-4+x))=0

We add all the numbers together, and all the variables

7(x-4)-(3x+4(x-4))+8=0

We multiply parentheses

7x-(3x+4(x-4))-28+8=0



We calculate terms in parentheses: -(3x+4(x-4)), so:

3x+4(x-4)

We multiply parentheses

3x+4x-16

We add all the numbers together, and all the variables

7x-16

Back to the equation:

-(7x-16)



We add all the numbers together, and all the variables

7x-(7x-16)-20=0

We get rid of parentheses

7x-7x+16-20=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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