7(x-4)+14=3(x-2)

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Solution for 7(x-4)+14=3(x-2) equation: 



7(x-4)+14=3(x-2)

We move all terms to the left:

7(x-4)+14-(3(x-2))=0

We multiply parentheses

7x-(3(x-2))-28+14=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

7x-(3x-6)-14=0

We get rid of parentheses

7x-3x+6-14=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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