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7(x-3)=2(x+5)-x
We move all terms to the left:
7(x-3)-(2(x+5)-x)=0
We multiply parentheses
7x-(2(x+5)-x)-21=0
We calculate terms in parentheses: -(2(x+5)-x), so:We get rid of parentheses
2(x+5)-x
We add all the numbers together, and all the variables
-1x+2(x+5)
We multiply parentheses
-1x+2x+10
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
7x-x-10-21=0
We add all the numbers together, and all the variables
6x-31=0
We move all terms containing x to the left, all other terms to the right
6x=31
x=31/6
x=5+1/6
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