7(x-3)=-3(-3-3x)-8

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Solution for 7(x-3)=-3(-3-3x)-8 equation: 



7(x-3)=-3(-3-3x)-8

We move all terms to the left:

7(x-3)-(-3(-3-3x)-8)=0

We add all the numbers together, and all the variables

7(x-3)-(-3(-3x-3)-8)=0

We multiply parentheses

7x-(-3(-3x-3)-8)-21=0



We calculate terms in parentheses: -(-3(-3x-3)-8), so:

-3(-3x-3)-8

We multiply parentheses

9x+9-8

We add all the numbers together, and all the variables

9x+1

Back to the equation:

-(9x+1)



We get rid of parentheses

7x-9x-1-21=0

We add all the numbers together, and all the variables

-2x-22=0

We move all terms containing x to the left, all other terms to the right

-2x=22

x=22/-2

x=-11

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