7(x-3)+6=8+4(2x+1)

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Solution for 7(x-3)+6=8+4(2x+1) equation: 



7(x-3)+6=8+4(2x+1)

We move all terms to the left:

7(x-3)+6-(8+4(2x+1))=0

We multiply parentheses

7x-(8+4(2x+1))-21+6=0



We calculate terms in parentheses: -(8+4(2x+1)), so:

8+4(2x+1)

determiningTheFunctionDomain
4(2x+1)+8

We multiply parentheses

8x+4+8

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

7x-(8x+12)-15=0

We get rid of parentheses

7x-8x-12-15=0

We add all the numbers together, and all the variables

-1x-27=0

We move all terms containing x to the left, all other terms to the right

-x=27

x=27/-1

x=-27

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