7(x-3)+4x=33-5(x-2)

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Solution for 7(x-3)+4x=33-5(x-2) equation: 



7(x-3)+4x=33-5(x-2)

We move all terms to the left:

7(x-3)+4x-(33-5(x-2))=0

We add all the numbers together, and all the variables

4x+7(x-3)-(33-5(x-2))=0

We multiply parentheses

4x+7x-(33-5(x-2))-21=0



We calculate terms in parentheses: -(33-5(x-2)), so:

33-5(x-2)

determiningTheFunctionDomain
-5(x-2)+33

We multiply parentheses

-5x+10+33

We add all the numbers together, and all the variables

-5x+43

Back to the equation:

-(-5x+43)



We add all the numbers together, and all the variables

11x-(-5x+43)-21=0

We get rid of parentheses

11x+5x-43-21=0

We add all the numbers together, and all the variables

16x-64=0

We move all terms containing x to the left, all other terms to the right

16x=64

x=64/16

x=4

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