7(x-3)+3(4+x)=-8

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Solution for 7(x-3)+3(4+x)=-8 equation: 



7(x-3)+3(4+x)=-8

We move all terms to the left:

7(x-3)+3(4+x)-(-8)=0

We add all the numbers together, and all the variables

7(x-3)+3(x+4)-(-8)=0

We add all the numbers together, and all the variables

7(x-3)+3(x+4)+8=0

We multiply parentheses

7x+3x-21+12+8=0

We add all the numbers together, and all the variables

10x-1=0

We move all terms containing x to the left, all other terms to the right

10x=1

x=1/10

x=1/10

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