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7(x-3)+2(x+1)=9x-19
We move all terms to the left:
7(x-3)+2(x+1)-(9x-19)=0
We multiply parentheses
7x+2x-(9x-19)-21+2=0
We get rid of parentheses
7x+2x-9x+19-21+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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