7(x-2+3)=(x+4)+2

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Solution for 7(x-2+3)=(x+4)+2 equation: 



7(x-2+3)=(x+4)+2

We move all terms to the left:

7(x-2+3)-((x+4)+2)=0

We add all the numbers together, and all the variables

7(x+1)-((x+4)+2)=0

We multiply parentheses

7x-((x+4)+2)+7=0



We calculate terms in parentheses: -((x+4)+2), so:

(x+4)+2

We get rid of parentheses

x+4+2

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We get rid of parentheses

7x-x-6+7=0

We add all the numbers together, and all the variables

6x+1=0

We move all terms containing x to the left, all other terms to the right

6x=-1

x=-1/6

x=-1/6

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