7(x-2)=5(x-3)+2x+1

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Solution for 7(x-2)=5(x-3)+2x+1 equation: 



7(x-2)=5(x-3)+2x+1

We move all terms to the left:

7(x-2)-(5(x-3)+2x+1)=0

We multiply parentheses

7x-(5(x-3)+2x+1)-14=0



We calculate terms in parentheses: -(5(x-3)+2x+1), so:

5(x-3)+2x+1

We add all the numbers together, and all the variables

2x+5(x-3)+1

We multiply parentheses

2x+5x-15+1

We add all the numbers together, and all the variables

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

7x-7x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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