7(x-2)=2(4+3x)+x

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Solution for 7(x-2)=2(4+3x)+x equation: 



7(x-2)=2(4+3x)+x

We move all terms to the left:

7(x-2)-(2(4+3x)+x)=0

We add all the numbers together, and all the variables

7(x-2)-(2(3x+4)+x)=0

We multiply parentheses

7x-(2(3x+4)+x)-14=0



We calculate terms in parentheses: -(2(3x+4)+x), so:

2(3x+4)+x

We add all the numbers together, and all the variables

x+2(3x+4)

We multiply parentheses

x+6x+8

We add all the numbers together, and all the variables

7x+8

Back to the equation:

-(7x+8)



We get rid of parentheses

7x-7x-8-14=0

We add all the numbers together, and all the variables

-22!=0

There is no solution for this equation

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