7(x-2)=2(3x+1)-11

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Solution for 7(x-2)=2(3x+1)-11 equation: 



7(x-2)=2(3x+1)-11

We move all terms to the left:

7(x-2)-(2(3x+1)-11)=0

We multiply parentheses

7x-(2(3x+1)-11)-14=0



We calculate terms in parentheses: -(2(3x+1)-11), so:

2(3x+1)-11

We multiply parentheses

6x+2-11

We add all the numbers together, and all the variables

6x-9

Back to the equation:

-(6x-9)



We get rid of parentheses

7x-6x+9-14=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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