7(x-2)=2(3x+1)

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Solution for 7(x-2)=2(3x+1) equation: 



7(x-2)=2(3x+1)

We move all terms to the left:

7(x-2)-(2(3x+1))=0

We multiply parentheses

7x-(2(3x+1))-14=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

7x-6x-2-14=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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