7(x-2)+6=2(x-4)

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Solution for 7(x-2)+6=2(x-4) equation: 



7(x-2)+6=2(x-4)

We move all terms to the left:

7(x-2)+6-(2(x-4))=0

We multiply parentheses

7x-(2(x-4))-14+6=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

7x-(2x-8)-8=0

We get rid of parentheses

7x-2x+8-8=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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