7(x-2)+2x=5(x+4)-38

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Solution for 7(x-2)+2x=5(x+4)-38 equation: 



7(x-2)+2x=5(x+4)-38

We move all terms to the left:

7(x-2)+2x-(5(x+4)-38)=0

We add all the numbers together, and all the variables

2x+7(x-2)-(5(x+4)-38)=0

We multiply parentheses

2x+7x-(5(x+4)-38)-14=0



We calculate terms in parentheses: -(5(x+4)-38), so:

5(x+4)-38

We multiply parentheses

5x+20-38

We add all the numbers together, and all the variables

5x-18

Back to the equation:

-(5x-18)



We add all the numbers together, and all the variables

9x-(5x-18)-14=0

We get rid of parentheses

9x-5x+18-14=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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